Question

There are 76 men and 69 women in a room. 29 of the men and 23 of the women earn more than $50,000 per year.

1. what is the probability of randomly selecting a person that earns more than $50,000 per year from this group?​

Answer 1

Answer: Our required probability is 0.358.

Explanation:

Since we have given that

Number of men = 76

Number of women = 69

Total number of people in a room = 76 + 69 = 145

Number of men earn more than $50000 per year = 29

Number of women earn more than $50000 per year = 23

Total number of people earn more than $50000 per year = 29+23=52

So, Probability that selecting a person that earns more than $50000 per year from this group is given by

`(52)/(145)\\\\=0.358`

Hence, our required probability is 0.358.