Answer: Estimated standard error for the sample mean difference would be 1.
Explanation:
Since we have given that
Mean of MD = 4.90
So, Sum of difference would be
![4.9* 9=44.1](https://img.qammunity.org/2020/formulas/mathematics/high-school/kst4mzw5p9cev29yvlv14s4toebg1du4ny.png)
S = 288
n = 9
We need to find the standard error for the sample mean differences.
Estimated standard error for the sampled mean difference would be
![\frac{\sqrt{Sum(D^2)-((sum(d)^2)/(n))}}{n(n-1)}}\\\\=\frac{\sqrt{288-(44.1^2)/(9)}}{9(9-1)}\\\\=0.99\\\\\approx 1](https://img.qammunity.org/2020/formulas/mathematics/high-school/b8qexj3e7uyd1cvam87qljnfs7u48wpy2a.png)
Hence, estimated standard error for the sample mean difference would be 1.