Question

In the reaction 2HgO(s) --> 2Hg(l) + O2(g) we measure the evolution of gas to determine the rate of reaction. At the beginning of the reaction (at 0 minutes), 0.02 L of O2 is present. After 10 minutes the volume of O2 is 0.36 L. What is the rate of reaction? Question 4 options:

Answer 1

0.034 L/min

Explanation:

The rate of reaction is the volume change (ΔV) divided by the time(t) and divided by the coefficient of the compound in the reaction. The coefficient of O₂ is 1, so:

R = (0.36 - 0.02)/10

R = 0.034 L/min