Question

Ava and Jiao each swam a two-lap swimming race. Ava took 31.49 seconds to finish her

first lap and 30.03 seconds to finish her second lap. Jiao finished her two-lap swimming
race 1.75 seconds faster than Ava
What was jiao's total swimming time in seconds after she finished her two-lap race?​

Answer 1

Answer: 59.77 s

Explanation:

We are told the total time for Ava
`t_(a)` is:

`t_(a)=t_(a1)+t_(a2)`

Where
`t_(a1)=31.49 s` for the first lap and
`t_(a2)=30.03 s` for the second lap.

Hence:

`t_(a)=31.49 s+30.03 s=61.52 s`

On the other hand, the total time for Jiao
`t_(j)` is:

`t_(j)=t_(a)-1.75 s`

`t_(j)=61.52 s-1.75 s`

Finally:

`t_(j)=59.77 s` This is Jiao's total time