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A hockey puck is given an initial speed of 30 m/s on a frozen pond. The puck remains on the ice and slides 104 m before coming to rest. The acceleration of gravity is 9.8 m/s 2 . What is the coefficient of friction between the puck and the ice?

User Mannopson
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1 Answer

3 votes

Answer:


\mu=0.44152

Step-by-step explanation:

t = Time taken

u = Initial velocity of puck = 30 m/s

v = Final velocity of puck = 0

s = Displacement of the puck = 104 m

a = Acceleration

g = Acceleration due to gravity = 9.8 m/s²


\mu = Coefficient of friction

Equation of motion


v^2-u^2=2as\\\Rightarrow a=(v^2-u^2)/(2s)\\\Rightarrow a=(0^2-30^2)/(2* 104)\\\Rightarrow a=-4.32692\ m/s^2


a=\mu g\\\Rightarrow \mu=(a)/(g)\\\Rightarrow \mu=(4.32692)/(9.8)\\\Rightarrow \mu=0.44152

Coefficient of friction between the puck and the ice is 0.44152

User Vvolkov
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