Question

Write an equation in slope-intercept form thats perpendicular to the given line and goes thru the point.

1. y=-3x + 4 (6,-2)
2. -2x -8y = 16 (4,5)
3.. x+y= 2 (8,5)
(PLS HELP ME I NEED THE ANSWER RIGHT NOW ITS URGENT)​

Answer 1

steps below

Explanation:

1. y=-3x + 4 (6,-2)

y' slope: 1/3 (perpendicular)

y' = mx + b

b = y' - mx = -2 - (1/3) x 6 = -4

equation: y' = 1/3 x - 4

2. -2x -8y = 16 (4,5)

8y = -2x - 16 y = -1/4 x - 2

perpendicular line slope: 4

b = y - mx = 5 - 4 x 4 = - 11

equation: y = 4x - 11

3. x+y= 2 (8,5)

y = -x + 2 slope: -1

perpendicular slope: 1

b = y - mx = 5 - 1 x 8 = -3

equation: y = x -3