Step-by-step explanation:
Given:
Δy = d
v₀ = 0
a = g
Find: v
v² = v₀² + 2aΔy
v² = (0)² + 2(g)(d)
v = √(2gd)
If we double d:
√(2g (2d))
√(4gd)
Compared to the first velocity:
√(4gd) / √(2gd)
√2
So the new velocity is √2 greater than the first velocity.
√2 v