Answer:
![2{x}^(2) + 7x - 4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1ozsc4rmim2mordzj91a93bpan7pr9amvs.png)
Explanation:
F [First terms] - Multiply the first terms in each set of parentheses FARTHEST TO THE LEFT
O [Outside terms] - Multiply the first term in the first set of parentheses FARTHEST TO THE LEFT by the last term in the second set of parentheses FARTHEST TO THE RIGHT
I [Inside terms] - Multiply the last term in the first set of parentheses FARTHEST TO THE RIGHT by the first term in the second set of parentheses FARTHEST TO THE LEFT
L [Last terms] - Multiply the last terms in each set of parentheses FARTHEST TO THE RIGHT
![(2x - 1)(x + 4) = 2{x}^(2) + 8x - x - 4 = 2{x}^(2) + 7x - 4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t1cv6pdh6ya8o9y27gh38i14rrfkfnispm.png)
I am joyous to assist you anytime.