Answer:
14875 kilojoules
Step-by-step explanation:
m = Mass of rocket = 1400 kg
F = Force of the propulsion = 80 kN
u = Initial velocity of the rocket = 30 m/s
v = Final velocity of the rocket = 55 m/s
Work done by the rocket is given by the kinetic energy
![K=(1)/(2)m(v^2-u^2)\\\Rightarrow K=(1)/(2)1400(55^2-30^2)\\\Rightarrow K=1487500\ J](https://img.qammunity.org/2020/formulas/physics/college/yzvub10tgj2laghd3ivdx60iyxz0utjbr9.png)
The net work done on the rocket is 1487500 Joules or 14875 kilojoules