Question

Which two statements are true for the cross illustrated by this Punnett square? R-smooth seeds, r-wrinkled seeds The F1 generation will be homozygous. The entire F1 generation will be hybrid. The entire generation will have smooth seeds. The entire generation will have wrinkled seeds. 50% of the generation will have wrinkled seeds.

Answer 1

It will be 2 & 3

Answer 2

The correct answers are: The entire F1 generation will be hybrid.

The entire generation will have smooth seeds.

Step-by-step explanation:

If the crossing individuals are both homozygote, then the F1 generation will be 100% heterozygote and will have smooth seeds.

The Punnet square is:

R R

r Rr Rr

r Rr Rr

F1 Genotype: 100% Heterozygote

Phenotype: 100% Smooth, which is the dominant trait.

• The F1 generation will be homozygous. False. As the crossing individuals are both homozygote, the whole F1 generation must be heterozygote.

• The entire F1 generation will be hybrid. True, all the F1 individuals will be heterozygote.

• The entire generation will have smooth seeds: True, as the smooth trait is dominant over the wrinkled trait and all the F1 individuals are heterozygotes, they all express the smooth trait.

• The entire generation will have wrinkled seeds: False because the wrinkled trait is the recessive one, so unless there is a homozygote individual for the trait, it can not be expressed.

• 50% of the generation will have wrinkled seeds: False. This would be the case in which a smooth heterozygote individual is crossed to a wrinkled homozygote individual. In the present example, both parental lines are homozygote.