Question

The combustion of hydrogen gas releases 286 kJ per mol of hydrogen. If 11.0 L of hydrogen at STP was burned to produce electricity, how long would it power a 100-watt (W) light bulb? Assume no energy is lost to the surroundings. (1 W = 1 J/s)

Answer 1

Answer: 21.7 min

Step-by-step explanation:

Power*time = energy, so time = energy/power =

Power=100W

Power=100 J/s

T= 127.6785kJ/100J/s = 1277 sec

T=1276.78sec/60min=21.3 min

Answer 2

T=21.7 min

Step-by-step explanation:

The volume of one mole of gas at STP is

22.4 L

10.0 L

then has

n'=10.0/22.4 moles

the total energy released is then

Et= (10.0/22.4)* 286 kJ

Et=127.678 KJ

Power*time = energy, so time = energy/power =

Power=100W

Power=100 J/s

T= 127.6785kJ/100J/s = 1277 sec

T=1276.78sec/60min=21.3 min