Question

3. Jenny crosses 2 hybrid pea plants. What is the probability that the offspring will be

short? Set-up and complete the punnett square below to solve this problem. (HINT: tt =
short, and TT & Tt = tall)

Answer 1

Twenty five percent

Step-by-step explanation:

Let us assume that the allele for tall pea plant be "T" and the allele for short pea plant be "t".

Also let us assume that "T" is dominant over "t"

A hybrid pea plant will have both the allele for tall and short plants.

Thus, genotype of hybrid pea plant would be "Tt"

Now if two hybrid pea plants are crossed, then following offspring are formed -

Tt * Tt

TT, Tt, Tt, tt

Thus, out of four only one offspring having "tt" genotype will produce short pea plants.

Thus, probability is equal to

`(1)/(4) * 100\\= 25`%

Answer 2

A punnet square is a diagram which is made to illustrate the percentages of the traits that will be passed on from the parents to the offsprings.

If jenny crosses a heterogenous tall dominant pea plant with a short homozygous pea plant then 50 percent of the offsprings will be short.

If Jenny crosses a tall, dominant homozygous pea plant with a short homozygous pea plant then all of the offspring will be tall and heterogenous dominant