Question

Please help me graph

Answer 1

Get the y-intercept from (-2, 3) then get other points by considering one point at a time

Answer 2

From general linear equation;

`{ \rm{y = mx + c}}`

m is the slope;

`{ \rm{y = - (1)/(2)x + c }}`

• When x is -2 and y is 3;

`{ \tt{3 = - ((1)/(2) * - 2) + c}} \\ \\ { \tt{3 = 1 + c}} \\ { \tt{c = 2}}`

Therefore our line has equation of

`{ \boxed{ \tt{y = - (1)/(2)x + 2 }}}`

OTHER POINTS.

`{ \tt{ \red{ {1}^(st) \dashrightarrow \: (0, \: 2)}}}`

• 
  `{ \rm{when \: x = 0, \: \: y = ( - (1)/(2) * 0) + 2 }} \\ { \rm{y = 2}}`

`{ \blue{ \tt{ {2}^(nd) \dashrightarrow \: (4, \:0) }}}`

• 
  `{ \rm{when \: x = 4, \: \: y = ( - (1)/(2) * 4) + 2 }} \\ { \rm{y = - 2 + 2 = 0}}`

`{ \green{ \tt{ {3}^(rd) \dashrightarrow \: (6, \: - 1)}}}`

substitute for x as 6