Question

A spring with constant 50 N/m is stretch 0.5 m. How much EPE does it have? A. 25 J B. 12.5 J C. 50 J D. 6.25 J

Answer 1

D. 6.25 J

Step-by-step explanation:

• EPE = 1/2*k*(Δx)²

∴ k = 50 N/m

∴ Δx = 0.5 m

⇒ EPE = 1/2*50 N/m*(0.5m)²

⇒ EPE = 6.25 N.m = 6.25 J