Question

You decide to build a small generator by rotating a coiled wire inside a static magnetic field of 0.38 T. You construct the apparatus by coiling wire into 4 loops of radius 0.20 m. If the coils rotate at 2.0 revolutions per second and are connected to a device with 200Ω resistance, calculate the average power PaveragePaverage supplied to that device.

Answer 1

0.0288 W

Step-by-step explanation:

`/omega=2 rev/s=2*2\pi= 12.56637 rad/s`

Energy, E is given by

`E=NBA\omega` where N is number of loops, A is area and B is static magnetic field

Substituting 4 for N, 0.38 T for B, and area calculated

`E=4*0.38*(\pi*0.2^(2))*12.56637=2.400288 V`

E=2.4 V

To get the average power

`P_(average)=\frac {E^(2)}{R}` where R is resistance

`P_(average)=\frac {2.4^(2)}{200}=0.0288 W`