Question

If an electron is accelerated from rest through a potential difference of 9.9 kV, what is its resulting speed?

e=1/60 x 10^-19 C
K=8.99 x10^9
Me=9.11 x 10^-31

Answer 1

Speed of the electron will be
`v=5.896* 10^7m/sec`

Step-by-step explanation:

We have given that charge on electron
`e=1.6* 10^(-19)C`

Mass of electron
`m=9.11* 10^(-31)kg`

Potential difference =
`V=9.9KV=9.9* 10^3volt`

Now according to energy conservation
`eV=(1)/(2)mv^2`

`1.6* 10^(-19)* 9.9* 10^3=(1)/(2)* 9.11* 10^(-31)v^2`

`v=5.896* 10^7m/sec`