Question

How many moles of acetic acid, CH3COOH, are contained within 24.71 g of
acetic acid?

Answer 1

0.4118 mol

Step-by-step explanation:

molar mass of CH3COOH = 12*2 + 4*1 +16*2 = 24+4+32= 60 g/mol

24.71 g / 60 (g/mol) = 0.4118 mol

Answer 2

0.41 moles of acetic acid

Step-by-step explanation:

moles are calculated as the division of compound mass by compound molar weight, that is:

moles of acetic acid = mass of acetic acid/ molar weight of acetic acid

The mass of acetic acid is 24.71 g and its molar weight is 2*12 + 4*1+ 2*16 = 60 g/mol, so

moles of acetic acid = 24.71/60 = 0.41 moles