Question

The graph of f(x) = x² has an

x-intercept
x-intercept
located?
at x = 0. Where will the
for h(x) = (x + 9)² be located

Answer 1

Explanation:

The graph of x^2 touches the point (0, 0) - where x and y = 0.

It intercepts the y-axis but just touches the x axis.

(x + 9)^2 will touch the point (-9, 0).