Question

URGENT!! Can someone help me with this?

A sample of oxygen gas has a volume of 2.1 L at 3.6 atm pressure and 200 K temperature.

What would the volume of this sample be at 1.0 atm and 400 K?

Answer 1

15.1L

Step-by-step explanation:

Given parameters:

Initial volume = 2.1L

Initial pressure = 3.6atm

Initial temperature = 200K

Final pressure = 1 atm

Final temperature = 400K

Unknown:

Final volume of the sample = ?

Solution:

To solve this problem, we are going to use the general gas law or the combined gas law which is expressed below:

P, V and T are pressure, volume and temperature

1 and 2 are the initial and final states

Now;

=

200V₂ = 3024

V₂ = 15.1L

Answer 2

15.1L

Step-by-step explanation:

Given parameters:

Initial volume = 2.1L

Initial pressure = 3.6atm

Initial temperature = 200K

Final pressure = 1 atm

Final temperature = 400K

Unknown:

Final volume of the sample = ?

Solution:

To solve this problem, we are going to use the general gas law or the combined gas law which is expressed below:

`(P_(1) V_(1) )/(T_(1) ) = (P_(2) V_(2) )/(T_(2) )`

P, V and T are pressure, volume and temperature

1 and 2 are the initial and final states

Now;

`(2.1 x 3.6)/(200)` =
`(1 x V_(2) )/(400)`

200V₂ = 3024

V₂ = 15.1L