Question

The sum of 444 consecutive integers is 326326326.
What is the second number in this sequence?

Answer 1

81581581

Explanation:

x=1st integer then (x+1), ( x+2), and (x+3) all add up to 326326326

Now,

x + x+1 + x+2 + x+3 = 326326326

Or, 4x +6 = 326326326

Or, 4x = 326326326-6

Or, 4x = 326326320

Or, x = 326326320/4

So, x= 81581580

So, the Second number is 81581581

Answer 2

82

Explanation:

Let's first figure out what the first number is and use that to solve for the next. The problem states that the numbers are consecutive. So the 2nd number word be 1 plus the first.

The sum of 4 consecutive numbers:

1st = x

2nd = x + 1

3rd = x + 2

4th = x + 3

The sum of 4 consecutive number is 326.

1st + 2nd + 3rd + 4th = 326

x + (x + 1) + (x + 2) + (x + 3) = 326

Combine like terms:

4x + 6 = 326

Then we subtract 6 from both sides to isolate 4x:

4x + 6 - 6 = 326 - 6

4x = 320

Then we divide both sides by 4 to isolate x:

4x/4 = 320/4

x = 80

So the first number is 79

Now to get the second, let's just add 1.

80 + 1 = 81

Let's check if our answer would be correct:

80 + 81 + 82 + 83

= 326