112k views
16 votes
Water flowed out of a tank at a steady rate. A total of 18 and one-half gallons flowed out of the tank in 4 and one-fourth hours. Which expression determines the quantity of water leaving the tank per hour?

StartFraction 17 over 4 EndFraction divided by StartFraction 36 over 2 EndFraction
StartFraction 36 over 2 EndFraction divided by StartFraction 17 over 4 EndFraction
StartFraction 17 over 4 EndFraction divided by StartFraction 37 over 2 EndFraction
StartFraction 37 over 2 EndFraction divided by StartFraction 17 over 4 EndFraction

User MHollis
by
4.6k points

2 Answers

6 votes

Answer:

D

37/2 divided by 17/4

Step-by-step explanation:

edge 2020

User Josh Heald
by
5.6k points
14 votes

Answer:

StartFraction 37 over 2 EndFraction divided by StartFraction 17 over 4 EndFraction

Step-by-step explanation:

This problem deals with solving and find the rate at which water flowed out of the tank.

Quantity of water that flowed out of the tank = 18
(1)/(2) gallons =
(37)/(2)gallons

Time taken = 4
(1)/(4)hr =
(17)/(4)hr

Now to find the rate;

Rate of water flow =
(Quantity of water )/(Time taken)

Rate of water flow =
(37)/(2) /
(17)/(4)

=
(37)/(2) x
(4)/(17)

=
(74)/(17)gallons/hr

User Pupot
by
5.9k points