Answer:
T= 633.51 x 10⁻²⁸ N.m
Step-by-step explanation:
Given that
r= 4.52 x 10⁻¹¹ m
v= 2.8 x 10⁶ m/s
B= 6.29 mT
We know that charge on electron Q
Q= 1.6 x 10⁻¹⁹ C
The time period t
t=2πr / v
Now by putting the values
t=(2 x π x 4.52 x 10⁻¹¹ ) / (2.80 x 10⁶)
t= 10.13 x 10⁻¹⁷ s
So current I
I = Q/t
I=(1.6 x 10⁻¹⁹)/(10.13 x 10⁻¹⁷)
I= 1.57 mA
The torque T given as
T = I A B
A= π x (4.52 x 10⁻¹¹) ² m²
A= 64.15 x 10⁻²² m²
T = I A B
T = 1.57 x 10⁻³ x 64.15 x 10⁻²² x 6.29 x 10⁻³ M.m
T= 633.51 x 10⁻²⁸ N.m