Answer: 0.2420
Explanation:
Let x be a random variable that represents the number of cars passed through the intersection per day .
As per given , we have


We assume that the number of cars on the interchange is approximately normally distributed.
∵

Then for x= 620,000,
The probability more than 620,000 use the interchange on a random day :-

Hence, the probability more than 620,000 use the interchange on a random day= 0.2420