Question

Write an equation for the line that passes through the points (4,8) and (6,2)

Answer 1

The equation for the line that passes through the points (4,8) and (6,2)

is y + 3 x -20 = 0

Explanation:

Here, the given points are (4,8) and (6,2)

So, the slope of the equation joining two points is
`m = (y_2- y_1)/(x_2 - x_1)  = (2-8)/(6-4) =(-6)/(2)  = -3\\`

⇒Slope of the given line is m = -3

Now, by POINT SLOPE FORMULA:

Equation of a line is (y - y0) = m (x-x0)

Here, equation of the line with (x0, y0) = (6,2) is

y - 2 = (-3)(x - 6)

or, y -2 = -3x + 18

⇒ y+ 3x -20 = 0

Hence, the equation for the line that passes through the points (4,8) and (6,2) is y+ 3x -20 = 0