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The sound source of a ship’s sonar system operates at a frequency of 22.0 kHz. The speed of the sound wave emitted by the source in sea water is 1510 m/s. What is the difference in frequency between the directly radiated waves and the waves reflected from a whale traveling directly toward the ship at 4.95 m/s

User Ryanzec
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1 Answer

4 votes

Answer:


\Delta f= 144.71KHz

Step-by-step explanation:

We define two formulas. Firt for the stationary object and then for the shpo,

The frequency formula for the stationary is,


f_(Lr)=(V+V_w)/(V)f^1\\f_(S)=(V)/(V-V_w)f^2

We need to find the difference or the rate of the relevant frequencies, that is


\Delta f= f_(Lr)-f_S\\\Delta=f(2V_w)/(V-V_w)

With the dates that we have, we only make a substitution,


f=22 KHz\\V_w = 4.95m/s\\V= 1510m/s


\Delta f= (22.0KHz)((2(4.95))/(1510-4.95))


\delta f= 144.71KHz

User Yue Wang
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