Answer:
a) v = √(GM/R), b) K = ½ G m M /R and d) T = 2π R√(R/GM)
Step-by-step explanation:
This problem should use the law of universal gravitation
F = G m M / r²
a) For this part we use Newton's second law where acceleration is centripetal
F = m a
Centripetal acceleration is
a = v² / r
F = m v² / r
G m M / r² = m v² / r
G M / r = v²
We use the distance (R) measured from the center of the planet
v = √(GM / R)
b) the expression for kinetic energy is
K = ½ m v²
K = ½ m G M / R
K = ½ G m M / R
d) as the velocity module is constant, we can use the equation and uniform motion
v = d / T
T = d / v
The distance is the length of the circle
d = 2π R
T = 2π R / √(GM / R)
T = 2π R √ (R / GM)