Answer:
In 6% of the projects was Bautista selected, but Aaron was not
Explanation:
Building the Venn diagram, I am going to say that:
-A is the number of projects that Aaron was selected.
-B is the number of projects that Bautista was selected.
We have that:

In which a is the number of projects that only Aaron was selected and
is the number of projects that both were selected.
By the same logic, we also have that:

In what percentage of the projects was Bautista selected, but Aaron was not
There were b projects that Bautista was selected and Aaron not. The total number projects is 50. So this percentage is b/50.
We start finding the values from the intersection.
12 of the projects, they both were selected. This means that

Bautista was selected for 15 of the projects, so




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In 6% of the projects was Bautista selected, but Aaron was not