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Write the equation of a line that is perpendicular to y=7/5x+6 and that passes through the line (2,-6)

User Emmanu
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1 Answer

5 votes

Answer:

The Answer is: y = -5/7x - 4 4/7

Explanation:

The given equation:

y = 7/5x + 6

The slope is: 7/5

The slope of a line perpendicular to this line is the negative inverse:

-5/7

Take the given point, (2, -6) and use the point slope form of the equation:

y - y1 = m(x - x1)

y - (-6) = -5/7(x - 2)

y + 6 = -5/7x + 10/7

Subtract 6 from both sides:

y = -5/7x + 10/7 - 6

Find a common denominator:

y = -5/7x + 10/7 - 42/7

y = -5/7x -32/7

y = -5/7x - 4 4/7

User Nouman Tahir
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