Question

There are 412 students and 20 teachers taking buses on a trip to a museum. Each bus can seat a maximum of 48. Which inequality gives the least number of buses, b, needed for the trip?

Answer 1

10 buses are needed.

9 buses will only be able to take 468 people.

Explanation:

There are 461 + 20 = 481 people altogether needing transport. Each bus can take at most 52 people. The number of buses needed = 482 ÷ 52. 482 ÷ 52 = 9.25 buses. You might be tempted to round down to 9 buses (because of the 2 that follows the decimal) However, if there are 9 buses, 9 × 52 = 468 people can be taken There will still be 13 people to be transported. This is an example of where you need to round UP to the next whole number. 10 buses are needed. In reality it means that not all the buses will be full, but 10 buses are needed to ensure that everyone gets a ride to the museum.

Answer 2

Answer: 48 b ≤432

Explanation:

Hi, to answer this question we have to analyze the information given:

• Number of students: 412
• Number of teachers: 20
• Bus capacity: 48 people per bus

So, first we have to add the number of students and the number of teachers, to obtain the total number of people.

412+20 = 432 people

Since each bus can seat a maximum of 48, we have to multiply 48 by the number of buses (b) and that expression must be less or equal to 432.

48 b ≤ 432