Question

Can someone help me with 9, 10, & 11

Answer 1

1) For, m = 3/4 , (0,4) , 4y - 16 - 3x = 0 is the equation of line.

2) For, m = 4 , (-2,-5) , y - 4x - 4 = 0 is the equation of line.

3) For, m = -1/3 , (4,-1) , x + 3y -1 = 0 is the equation of line.

Explanation:

If m is the slope and (x0,y0) is the point on any given equation, then

by POINT SLOPE FORMULA:

The line equation is given as (y - y0) = m (x -x0)

Now , here:

1) m = 3/4 , (x0, y0) = (0.4)

So,, the equation of line is
`(y-4) = (3)/(4) (x-0)\\or, 4(y-4)  =  3x`

on simplification, 4y - 16 - 3x = 0 is the equation of line.

2) m = 4 , (x0, y0) = (-2.-5)

So,, the equation of line is
`(y-(-5)) = 4 * (x-(-2))\\or, (y+4)  =  4(x+2)`

on simplification, y - 4x - 4 = 0 is the equation of line.

3) m = -1/3 , (x0, y0) = (4, -1)

So,, the equation of line is
`(y-(-1)) = (-1)/(3) (x-4)\\or, 3(y+1)  =  -(x-4)`

on simplification, x + 3y -1 = 0 is the equation of line.