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The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean μ, the actual temperature of the medium, and standard deviation σ. What would the value of σ have to be to ensure that 95% of all readings are within 0.5° of μ? (Round your answer to four decimal places.) σ =

User NDavis
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1 Answer

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Answer: 0.2551

Explanation:

Given : The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean μ, the actual temperature of the medium, and standard deviation σ.

Significance level :
\alpha=1-0.95=0.05

The critical z-value for 95% confidence :
z_(\alpha/2)=1.960 (1)

Since ,
z=(x-\mu)/(\sigma) (where x be any random variable that represents the temperature reading from a thermocouple.)

Then, from (1)


(x-\mu)/(\sigma)=1.96\\\\ x-\mu=1.96\sigma (2)

Also, all readings are within 0.5° of μ,

i.e.
x-\mu<0.5

i.e.
1.96\sigma<0.5 [From (2)]

i.e.
\sigma<(0.5)/(1.96)=0.255102040816

i.e.
\sigma\approx0.2551

The required standard deviation :
\sigma=0.2551

User Kvaruni
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