Question

You pull straight up on the string of a yo-yo with a force 0.24 N, and while your hand is moving up a distance 0.17 m, the yo-yo moves down a distance 0.26 m. The mass of the yo-yo is 0.057 kg, and it was initially moving downward with speed 2.4 m/s.

Answer 1

The transnational kinetic energy of the yo-yo is 0.083 J.

Step-by-step explanation:

Given that,

Force=0.24 N

Distance in up= 0.17 m

Distance in down = 0.26 m

Mass of yo-yo = 0.057 kg

Initial speed = 2.4 m/s

Suppose we find the increase in the transnational kinetic energy of the yo-yo

The transnational kinetic energy is equal to the change in potential energy.

We need to calculate the transnational kinetic energy of the yo-yo

Using conservation of energy

`\Delta K.E=(mg-F)h`

Where, F = force

h = height

m = mass of yo-yo

Put the value into the formula

`\Delta K.E=(0.057*9.8-0.24)*0.26`

`\Delta K.E=0.083\ J`

Hence, The transnational kinetic energy of the yo-yo is 0.083 J.