Answer:
b.4
Step-by-step explanation:
Let
Magnetic field produced=B
Charge on particle=q
Mass of charged particle=m
Radius=2r
We have to find the k.E of the particle by what factor increases when radius taken twice .
Maximum K.E of particle in cyclotron=
![(1)/(2)(q^2B^2r^2)/(m)](https://img.qammunity.org/2020/formulas/physics/college/v2s8ppo64byn6hwc84bxch7bn347x42xyo.png)
Substitute radius= 2r
Then, maximum kinetic energy of particle =
![(q^2B^2(2r)^2)/(2m)=4(q^2B^2r^2)/(2m)=4\cdot K.E_(max)](https://img.qammunity.org/2020/formulas/physics/college/7ug5idckj0ahln9y9jlfn8adjdqbhimyq3.png)
Hence, the maximum kinetic energy of the particle increases by 4 when radius taken twice.
Answer: b.4