Question

Which two points are on the graph of M(a) = - 3/4a-12?

Choose exactly two answers that are correct.
(-9,0)
(-16, 0)
(0, 12)
(0, -12)

Answer 1

(-16, 0) and (0,-12) are exactly two points on the graph of the given equation.

Explanation:

Here, the given expression is :
`M(a) = -(3)/(4) a-12`

Here, let M(a) = b

⇒The equation becomes
`b = -(3)/(4) a-12`

Now, check for all the given points for (a,b)

1) FOR (-9,0)

`RHS  is  -(3)/(4) (-9)-12  =   -5.25 \\eq 0`

Hence, (-9,0) is NOT on the graph.

2) FOR (-16,0)

Here, LHS = b = 0

and
`RHS  =   -(3)/(4) (-16)-12  = 12-12  = 0`

Hence, LHS = RHS = 0 So, (-16,0) is on the graph.

3) FOR (0,12)

Here, LHS = b = 12

`RHS  is  -(3)/(4) (0)-12  =   -12  \\eq 12`

Hence, (0,12) is NOT on the graph.

4) FOR (0,-12)

Here, LHS = b = -12

`RHS  is  -(3)/(4) (0)-12  =   -12`

and LHS = RHS = -12

Hence, (0,-12) is on the graph.

Hence, (-16, 0) and (0,-12) are exactly two points on the graph of the given equation.