Question

A tightrope walker wonders if her rope is safe. Her mass is 60 kg and the length of the rope is about 20 m. The rope will break if its tension exceeds 9200 N. Part A What is the smallest angle at which the rope can bend up from the horizontal on either side of her to avoid breaking?

Answer 1

`\theta = 1.83\°`

Step-by-step explanation:

To give solution to this problem we need to apply the second law of Newton.

That is,

`F=mg`

We make summation of force in Y,

`\sum F_y = 0`

`2Tsin\theta - mg = 0`

Solving for
`\theta`

`2tsin\theta = mg`

`sin\theta = (mg)/(2T)`

`sin\theta = (60*9.8)/(2*9200)`

`sin\theta = 0.0319`

`\theta = sin^(-1)(0.0319)`

`\theta = 1.83\°`