Question

How many ounces of 15% alcohol solution must be mixed with 11 ounces of a 20% alcohol solution to make 16% alcohol solution

Answer 1

44 ounces

Explanation:

Begin by setting up your equation in the following format:

(Percent)(Amount) + (Percent)(Amount) = (Percent)(Amount + Amount)

In this case, your equation should look like this:

(0.15)(x) + (0.20)(11) = (0.16)(x + 11)

where x stands for the number of ounces of the 15% alcohol solution needed.

Next, we can begin simplifying to solve for x. Your work should look similar to this:

(0.15)(x) + (0.20)(11) = (0.16)(x + 11)

0.15x + 2.2 = (0.16)(x + 11)

~ Multiply both sides by 100 to eliminate all of the decimals ~

15x + 220 = 16(x + 11)

15x + 220 = 16x + 176

15x = 16x - 44

-x = -44

x = 44

This means that 44 ounces of 15% solution must be mixed with 20% solution to make 16% solution

~Hope this Helps!~