Question

How many zeros are at the end of 458 · 885? Explain how you can answer this question without actually computing the number. (Hint: 10 = 2 · 5.) When this number is written in ordinary decimal form, each 0 at its end comes from a factor of , or one factor of 2 and one factor of . g

Answer 1

One zero

Explanation:

To find : number of zeroes at the end of product 458 · 885 .

It's given that when this number is written in ordinary decimal form, each 0 at its end comes from a factor of , or one factor of 2 and one factor of . g

First, we will find factors of 458 and 885 .

`458=2* 229\\885=3* 5* 59`

From this factorisation, we get

`458\cdot 885=2* 229* 3* 5* 59`

i,e,
`458\cdot 885=2* 3* 5* 59* 229`

Here, we noticed that we have one 2 and one 5, which makes
`2* 5=10`

So, we conclude that 458 · 885 ends at one zero .