Question

9. A 0.500 kg ball with a speed of 4.0 m/s strikes a stationary 1.0 kg target. The ball and target

stick together. If momentum is conserved, what is the total momentum of the ball and target
after the collision?
A. 0.0 kgm/s
B. 0.5 kgm/s
C. 1.0 kgm/s
D.2.0 kgm/s​

Answer 1

The total momentum of the ball and target after the collision is D. 2.0 kgm/s.

Step-by-step explanation:

In a collision, the total momentum of the system before the collision is equal to the total momentum after the collision, according to the principle of conservation of momentum.

Since the ball and target stick together after the collision, their final velocity will be the same.

The momentum of the ball before the collision is given by mass times velocity, which is -

= (0.500 kg)*(4.0 m/s) = 2.0 kgm/s.

The momentum of the target before the collision is zero since it is stationary.

Therefore, the total momentum of the ball and target after the collision is also 2.0 kgm/s.

Therefore, the correct answer is D. 2.0 kgm/s.

Answer 2

D. 2.0 kg m/s

Step-by-step explanation:

Momentum after = momentum before

p = (0.500 kg) (4.0 m/s) + (1.0 kg) (0 m/s)

p = 2.0 kg m/s