Answer:
246
Explanation:
In the statment is defined our Values.
First que have a 95% Confidence interval
That is exactly in a Standar normal distribution table equal to Z Score = 1.96
The proportion
= 0.20
And we can and Margin Error (ME) equal to 0.05
Using the formula for the Sample Size (N) through Proportion we have,
![N= \frac{Z_(score)^2*\hat{p}*(1-\hat{p})} {ME^2}](https://img.qammunity.org/2020/formulas/mathematics/college/airv44iqy1j5l2l8ivb2fkwhs18trf887z.png)
![N= (1.96^2* 0.20 * (1-0.20))/(0.05^2)](https://img.qammunity.org/2020/formulas/mathematics/college/v707y1bgelbg6aeotjmk8ihzsy11o8dgpm.png)
or 246