Question

How many Joules of energy are required to boil 350g of water at 100 degrees Celsius?

Answer 1

`Q_(vap)=7.90x10^5J`

Step-by-step explanation:

Hello!

In this case, since this is the vaporization process of water, we need to keep in mind that the enthalpy of vaporization of this compound is 2.256 kJ/g, for 350 g, we obtain:

`Q_(vap)=m*\Delta H_(vap)\\\\Q_(vap)=350g*2.256(kJ)/(g) *(1000J)/(1kJ) \\\\Q_(vap)=7.90x10^5J`

Because the process is carried out at 100 °C, the boiling temperature of water, already.

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