Question

- The sum of three consecutive integers is 21 larger

than twice the smallest integer. Find the integers.

Answer 1

The consecutive integers are:

18, 19, 20

Explanation:

Let the three consecutive integers be:

x

x+ 1

x+2

Now according to given conditions:

x + x+1 +x + 2 = 21 + 2x

Adding like terms:

3x + 3 = 21 + 2x

Taking terms with x on left side and constants on right side

3x - 2x = 21 - 3 (Sign of transferred terms will be changed)

x = 18

So the consecutive terms become:

x = 18

x + 1 = 19

x + 2= 20

I hope it will help you!