Question

A sample of O2, under occupies 500ml at 25.0°C. What volume will the sample occupy at 0.0°C

Answer 1

458ml

Step-by-step explanation:

According to charles law,
`$(V_(1))/(T_(1)) =(V_(2))/(T_(2)) $`

Given values,

Volume occupied
`$V_(2)=500ml$`

Temperature
`$T_(1)=25.0^(\circ)C=25+273=298K$`

Second temperature
`$T_(2)=0.0^(\circ)C=273K$`

Volume
`$V_(2)=?$`

From charles law,
`$V_(2)=(V_(1) * T_(2))/(T_(1))$ \\$=(500 * 273)/(298)$\\$=458ml$`

`$\therefore$` Volume occupied by the oxygen at 0.0°C is 458ml