Answer:
4 days
Explanation:
We need to use the probability functions of each of the intervals to know the Probability number and then use it in the expected value.
P(x>3 cargo ships) = 1-P(x<=3)
P(x>3) = 1-P(x<=3)
P(x>3) = 1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)]
![P(x>3) = 1 - [(e^(-2)2^0)/(01)+(e^(-2)2^1)/(11)+(e^(-2)2^2)/(21)+(e^(-3)2^3)/(31)]](https://img.qammunity.org/2020/formulas/mathematics/college/tldontokvzqexflcnh6f11to17tjhvdo8v.png)
P(x>3) = 1- [0.1353(1+2+2+1.33)]
P(x>3) = 1-0.856
P(x>3) = 0.1431
Als n=30, expected number is
E(x) =30*P(x>3)
E(x) = 30*0.1431
E(x) = 4.293
I expect 4.293 or 4 days per month the block being unable to hanlde all arriving ships