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A reindeer needs to pull a sleigh up a 30 degree incline. If the mass of the sleigh is 200 kg, and the coefficient of kinetic friction between the sleigh and the incline is 0.2, what speed will the sleigh have when it reaches the top of the incline? Assume the height of the incline is 10m.

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Answer:

v = 26.94 m/s

Step-by-step explanation:

given,

angle of inclination = 30°

mass of the sleigh = 200 kg

coefficient of kinetic friction = 0.2

height of inclination = 10 m

pull force be = 5000 N

now,.


T - f_s - mg sin \theta = m a


T - \mu N - mg sin \theta = m a


T - \mu mg - mg sin \theta = m a


a = (T)/(m) - \mu g - g sin \theta


a = (5000)/(200) - \0.2* 9.8 - 9.8 * sin 30^0


a = 18.14\ m/s^2


L = (10)/(sin 30)

L = 20 m

v² = u² + 2 as

v² = 0 + 2 x 18.14 x 20

v = 26.94 m/s

User Sandeep Sukhija
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