Answer:
v = 26.94 m/s
Step-by-step explanation:
given,
angle of inclination = 30°
mass of the sleigh = 200 kg
coefficient of kinetic friction = 0.2
height of inclination = 10 m
pull force be = 5000 N
now,.







L = 20 m
v² = u² + 2 as
v² = 0 + 2 x 18.14 x 20
v = 26.94 m/s