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Cu + H₂O → CuO + H₂ This equation shows that Cu is . This equation shows that H₂ is .

User Robince
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1 Answer

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Answer:

Cu is oxidized and H₂ is reduced.

Step-by-step explanation:

Given chemical equation,


$Cu + H_(2)O \to CuO + H_(2)$

On observing the equation, if we write the oxidation states of all elements in the compounds, we will get


$Cu^(0) + H_(2)^(+1)O^(-2) \to Cu^(+2)O^(-2) + H_(2)^(0)$

In this equation,

Oxidation number of 'Cu' is increased from 0 to 2. Hence it is oxidized. While the oxidation number of 'H₂' is decreased from +1 to 0. Hence it is reduced.

User Rhett
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