The integrals over B and T will be positive. Keeping fixed, is strictly increasing over D as increases, so the integrals over (i.e. the bottom/top left quadrants of D) is negative but the integrals over are *more* positive.
The integrals over R and L are zero. If we take , then , which is to say is symmetric across the -axis. For the same reason, the integral over all of D is also zero.
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