Answer:
The populaton in year 1991 will be of 5178.9 million of people
and the population in year 2020 will be of 8524.60 million of people
Explanation:
We measure the time t in years and let t=0 in the year 1950.
We measure the population P(t) in millions of people, then P(0)=2560 and P(10) = 3040.
Since we are assuming that dp/dt=kP, this theorem gives the following.
![P(t) = P(0)e^(kt)= 2560e^(kt)](https://img.qammunity.org/2020/formulas/mathematics/college/dm1pfvihqgzix1evpxlm1lzt2y1jyp18nd.png)
![P(10) = 2560 e^(10k) = 3040](https://img.qammunity.org/2020/formulas/mathematics/college/krt7ffpv3ez5ctjtdba4ch86csap2z578x.png)
![k=(1)/(10) ln (3040/2560) = 0.0171](https://img.qammunity.org/2020/formulas/mathematics/college/zt378wyaqh638rfkg7wpdzaacpcafookpt.png)
The relative growth rate is about 1.7% per year and the model is
![P(t) = 2560e^(0.017185t)](https://img.qammunity.org/2020/formulas/mathematics/college/e5x9yz452tseyg2qffd19alhmoj4z2pled.png)
Year 1991 is equal in our formula to 41 and year 2020 is equal to 70. Replacing,
![P(41) = 2560e^(0.017185(41))=5178.89](https://img.qammunity.org/2020/formulas/mathematics/college/an2smzmmo3a7m8jgvv0n3ox5r0dsxxyto6.png)
![P(70) = 2560e^(0.017185(70))=8524.60](https://img.qammunity.org/2020/formulas/mathematics/college/vkexy9jnzuv0w0bb8qfutppp88c3x58txo.png)
Therefore the populaton in year 1991 will be of 5178.9 million of people and the population in year 2020 will be of 8524.60 million of people