Question

The fizz produced when an Alka-Seltzer tablet is dissolved in water is due to the reaction between sodium bicarbonate (NaHCO₃) and citric acid (H₃C₆H₅O₇):

3NaHCO₃(aq) + H₃C₆H₅O₇(aq) --------> 3CO₂(g) + 3H₂O(l) + Na₃C₆H₅O₇(aq)
In a certain experiment 1.00g of sodium bicarbonate and 1.00g of citric acid are allowed to react.
How many grams of carbon dioxide form?

Answer 1

0.47g of
`CO_(2)`

Step-by-step explanation:

1. Balanced equation:

3NaHCO₃(aq) + H₃C₆H₅O₇(aq) --------> 3CO₂(g) + 3H₂O(l) + Na₃C₆H₅O₇(aq)

2. Find the limiting reagent between the reactants:

-For the
`NaHCO_(3)`:

`1gNaHCO_(3)*(1molNaHCO_(3))/(84gNaHCO_(3))=0.012molesNaHCO_(3)`

Divide the number of moles between the stoichiometric coefficient of the
`NaHCO_(3)`:

`(0.012)/(3)=0.004`

-For the
`H_(3)C_(6)H_(5)O_(7)`:

`1gH_(3)C_(6)H_(5)O_(7)*(1molH_(3)C_(6)H_(5)O_(7))/(192gH_(3)C_(6)H_(5)O_(7))=0.005molesH_(3)C_(6)H_(5)O_(7)`

Divide the number of moles between the stoichiometric coefficient of the
`H_(3)C_(6)H_(5)O_(7)`:

`(0.005)/(1)=0.005`

The smallest number is the 0.004 therefore, the limiting reagent is the sodium bicarbonate.

3. Calculate the grams of carbon dioxide:

`1gNaHCO_(3)*(1molNaHCO_(3))/(94gNaHCO_(3))*(3molesCO_(2))/(3molesNaHCO_(3))*(44gCO_(2))/(1molCO_(2))=0.47gCO_(2)`