Question

acrylonitrile c3h3n is the starting material for the production of a type of widely used plastic called acrylics. acrylonitrile can be prepared from propylene, C3H6 by reaction with ammonia and oxygen. find the percent yield of acrylonitrile if the reaction yield is 91g when 84 g of propylene and 34 g of ammonia are reacted

Answer 1

85.85 %

Step-by-step explanation:

The formula for the calculation of moles is shown below:

`moles = (Mass\ taken)/(Molar\ mass)`

Given: For propylene

Given mass = 84 g

Molar mass of propylene = 42 g/mol

Moles of propylene = 84 g / 42 g/mol = 2 moles

Given: For ammonia

Given mass = 34 g

Molar mass of ammonia = 17 g/mol

Moles of ammonia = 34 g / 17 g/mol = 2 moles

According to the given reaction:

`2C_3H_6 + 2NH_3 + 3O_2 \rightarrow 2C_3H_3N + 6H_2O`

2 moles of ammonia react with 2 moles of propylene to give 2 moles of acrylonitrile.

Thus, Moles of acrylonitrile = 2 Moles

Molar mass of acrylonitrile = 53 g/mol

Mass of acrylonitrile = Moles × Molar mass = 2 × 53 g = 106 g

Theoretical yield = 106 g

Given experimental yield = 91 g

% yield = (Experimental yield / Theoretical yield) × 100 = (91/106) × 100 = 85.85 %